Question

Hasan buys two kinds of cloth meters for school uniforms, shirt material that costs him ₹50 per metre and trouser material that costs him ₹90 per metre.
For every 3 meters of the shirt material he buys 2 metres
of the trouser material. He sells the materials at 12% and 10% profit respectively. His total sale is 36,600.
How much trouser material did he buy?

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Answer 1

Step-by-step explanation:

Let ratio between shirt material and trouser material be 3x:2x3x:2x.

The cost of shirt material = 50×3x=150x50×3x=150x

The selling price at 12% gain:-

$= \frac{100+12}{100}\times150x100100+12×150x</p><p>.$

$90\times2x=180x90×2x=180x$

The selling price at 12% gain

$= \frac{100+P\%}{100}\times CP100100+P%×CP$

= 

$\frac{100+10}{100}\times180x100100+10×180x$

$= \frac{110}{100}\times180x=198x100110×180x=198x$

According to the question,

168x+198x=36,600168x+198x=36,600

$\Rightarrow366x=36600⇒366x=36600$

$\Rightarrow x=\frac{36600}{366}=100⇒x=36636600=100 meters.</p><p>$

Now, trouser material = 2x=2\times1002x=2×100

= 200 meters

Hence, Hasan bought 200 meters of the trouser material.

Answer 2

Step-by-step explanation:

1.2cm.

(Angle of a rectangle)

By Pythagoras thearam

BD² = BC ² + = 35²+

BD2= 1225 + 144

BD