Math, asked by savithashyju77, 1 month ago

Hasan buys two types of clothe meterias for school meterials shirt metirial cost him rs 50 per meter and trouser metirial that cost him rs 90 per meter for every three meters of the shirt metirial he buys two meters of the trouser metirial he sells the metirial at 12% and 10% respectively his total sale is rs 36,600hiw much trouser metirial did he buy​

Answers

Answered by shahistaa14
0

Answer:

janam fidaye haidari ya Ali Ali Ali janam fidaye haidari ya Ali ali ali

Answered by mishrapiyushh1234
0

Answer:

Dont know

Step-by-step explanation:

Solution:

Let ratio between shirt material and trouser material be 3x:2x3x:2x.

The cost of shirt material = 50\times3x=150x50×3x=150x

The selling price at 12% gain = \frac{100+P\%}{100}\times CP

100

100+P%

×CP

= \frac{100+12}{100}\times150x

100

100+12

×150x

= \frac{112}{100}\times150x=168x

100

112

×150x=168x

The cost of trouser material =

90\times2x=180x90×2x=180x

The selling price at 12% gain = \frac{100+P\%}{100}\times CP

100

100+P%

×CP

= \frac{100+10}{100}\times180x

100

100+10

×180x

= \frac{110}{100}\times180x=198x

100

110

×180x=198x

According to the question,

168x+198x=36,600168x+198x=36,600

\Rightarrow366x=36600⇒366x=36600

\Rightarrow x=\frac{36600}{366}=100⇒x=

366

36600

=100 meters.

Now, trouser material = 2x=2\times1002x=2×100

= 200 meters

Hence, Hasan bought 200 meters of the trouser material.

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