Question

HASSAN BUYS TWO KINDS OF CLOTH MATERIALS FOR SCHOOL UNIFORMS,SHIRT MATERIALS THAT COST HIM RUPEES 50 PER METER AND TROUSER MATERIAL THAT COST HIM RUPEES 90 PER METER.FOR EVERY 3 METERS OF THE SHIRT MATERIALS HE BUYS 2 METERS OF THE TROUSER MATERIAL HE SELLS THE MATERIALS AT 12% AND 10% PROFIT RESPECTIVELY . HIS TOTAL SALE IS 36600 RUPEES HOW MUCH TROUSER MATERIAL DID HE BUY?

Answer 1

Answer:

Let material bought for trousers and shirts be 2x meters and 3x meters respectively.

Cost price of 2x metres of trouser material at Rs. 90 per metre =Rs(90×2x)=Rs180x and;

Cost price of 3x metres of shirt material at Rs. 50 per metre =Rs(50×3x)=Rs150x

Given, profit in case of shirt material = 12%

$</em></strong><strong><em>I</em></strong><strong><em>t</em></strong><strong><em>'</em></strong><strong><em>s \: </em></strong><strong><em>S</em></strong><strong><em>.</em></strong><strong><em>P</em></strong><strong><em>. = </em></strong><strong><em>R</em></strong><strong><em>s(150 \times \frac{112}{100})$

$= </em></strong><strong><em>R</em></strong><strong><em>s168x$

Also, profit in case of trouser material = 10%

$</em><em>I</em><em>ts \: </em><em>S.</em><em>P</em><em>.</em><em> = </em><em>R</em><em>s(180 \times \frac{110}{100} )$

$= </em><em>R</em><em>s198x$

Total selling price =Rs.(168x+198x)

=Rs.366x

But the total selling price is given as Rs. 36600.

$366x = 36600$

$=> x = \frac{36600}{366}$

$x = 100$

Thus, the trouser material purchased:-

=2×100m

=200m

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Answer 2

Step-by-step explanation:

Let material bought for trousers and shirts be 2x meters and 3x meters respectively.