Hat is the mass of glucose required to produce 44 g of co2 on complete combustion?
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The reaction is : C6H12O6 + 6 O2 → 6 H2O + 6 CO2
Hence, 180g of glucose is needed to produce 264 g of CO2
So, for producing 44 g of CO2, 180*64/264 g of glucose is needed = 180/6 = 30 g
Hence, 30 g of glucose is required to produce 44 g of CO2 upon complete combustion.
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