Question

hatin
und sy =5x+4y=14
4x+5y=13​

Answer 1

Answer:

5x+4y=14........eq1st

4x+5y=13........eq2nd

Now multiply eq1st by 4 and eq 2nd by 5

(5x+4y=14)4

(4x+5y=13)5

20x+16y=56.....eq3

20x+25y=65......eq4

Now subtract eq4 by eq 3

20x+25y=65

20x+16y=56

- - -

0+9y=9

y=9/9

y=1......eq5th

now put eq5th in eq3rd

20x+16y=56

20x+16×1=56

20x+16=56

20x=56-16

20x=40

x=40/20

x=2

Step-by-step explanation:

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