have?
7. Raj has a sum of 800 in the form of den
of notes be 50, find the number of notes of each typ
8. Sunita has 9 in fifty-paise and twenty-five paise coins. She has twice at
five paise coins as she has fifty-paise coins. How many coins of each kind doesshe have this question solve please
Answers
Step-by-step explanation: 7 slove
Let the number of 10Rs notes be x Number of 20Rs notes be 50 – x Amount due to 10Rs notes = 10 × x = 10x Amount due to 20Rs notes = 20 × (50 – x) = 1000 – 20x So the total amount is Rs 800 10x + 1000 – 20x = 800 -10x = 800 – 1000 -10x = -200 x = -200/-10 = 20 ∴ The number of 10Rs notes is 20 Number of 20Rs notes are 50 – 20 = 30
8slove
Let 50 paise coins be x in number.
Therefore 25 paise coins are 2x in number.
Value of 50 paise coins is 50x and value of 25 paise coins is 25 x 2x = 50x.
Total value is 900 paise.
Therefore, 50x + 50x = 900.
100x = 900.
x = 9.
Therefore, no. of coins of 50 paise is 9 and no of coins of 25 paise is 18.
Total coins = 27.
Answer:
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Step-by-step explanation:
7) Let the numbers of 10 rupees notes = x
numbers of 20 rupees notes = 50 - x
According to the condition, we get
10x + 20(50 - x) = 800
→ 10x - 20x + 1000 = 800
→ -10x = -200
→ x = 20 = numbers of 10 rupees notes
numbers of 20 rupees notes = 50 - x = 50 - 20 = 30
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8) Let the number of fifty paise coins =x
Therefore the number of twenty five paise coins =2x
Value of fifty paise coins =x×50 paise = Rs. 50x /100 = Rs. x/2
Value of twenty five paise coins =2x × 25 paise
=2x × 25/100 = 2x × 1/4 = Rs. x/2 v
Total value of all coins = Rs. ( x/2 + x/2)
But the total value of the money is Rs.9
⇒ ( x/2 + x/2) = 9
⇒ 2x / 2 = 9
∴ x=9
Therefore number of fifty paise coins =x=9
Number of twenty paise coins =2x=2×9=18