Math, asked by EndlessHope, 11 months ago

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Answered by LovelyG
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Answer:

dy =  \frac{ \frac{1.(x + 1) - 1.(x - 1)}{(x + 1) {}^{2} } }{2 \sqrt{ \frac{x - 1}{x+ 1} } } . \: dx \\  \\ dy =  \frac{ \frac{x + 1 - x + 1}{(x + 1) {}^{2} } }{2 \sqrt{ \frac{x - 1}{x + 1} } } . \: dx \\  \\ dy =  \frac{ \frac{2}{(x + 1) {}^{2} } }{2 \sqrt{ \frac{x - 1}{x + 1} } }  . \: dx\\  \\ dy =  \frac{ \cancel2}{ \cancel2 \: . \: (x + 1) {}^{2}   \: . \: \sqrt{ \frac{x - 1}{x + 1} } }  \\  \\ \boxed{ \bf dy =  \frac{1}{(x + 1) {}^{2}  \:.  \:  \sqrt{ \frac{x - 1}{x + 1} } }  \:  .\: dx}

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Answered by Anonymous
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