have a look at this ...
(BE)² = MPB, where B,E,M and P are distinct integers then find M .
it is from real numbers of class 10th mathematics . :)
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Square of Number always ends with 1,4,5,6,9 and 00.
B can be 1,4,5,6, 9 only here . since B , E,M , P are distinct.
(4E)^2 = results in 4- digit number . so B = 1 ;
(1E)^2 = MP1 ; if units digit of a square is 1 then the num shud end with 1 or 9 .since all are distinct E =9 .
=> (19)^2 = 361 ; M=3
B can be 1,4,5,6, 9 only here . since B , E,M , P are distinct.
(4E)^2 = results in 4- digit number . so B = 1 ;
(1E)^2 = MP1 ; if units digit of a square is 1 then the num shud end with 1 or 9 .since all are distinct E =9 .
=> (19)^2 = 361 ; M=3
pahiroy1221:
thanx buddy :)
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