Question

have any charge on copper ring when it in magnetic field ​

Answer 1

Explanation:

emf induced = rate of change of flux =

dtd( A . B )

. As the two rings are identical the area of both the rings are same. Hence the flux and therefore the rate of change of flux in both is the same. Therefore emf induced in both is same.

Electric field =

length

emf

. As both the rings are identical, their length is same.

And hence the electric field in both is the same.