Question

Haw much work will be done in bringing a charge of 5.0 milicolombs from infinity to a point p at which the potential is 12volt?

Answer 1

Answer:-

W = 0.06 J

Given :-

Q = $5 \times 10^{-3} C$

V = 12 v

To calculate :-

The work done to move the charge from infinity to point P.

Solution :-

Potential Difference :- The total amount of work to be done to bring a charge from infinity to a point in an electric field is called potential difference.

Now, by using the formula of potential difference :-

$\boxed{\sf{ V = \dfrac{W}{Q}}}$

also,

W = V × Q

Put the given value,

$W = 12 \times 5 \times 10^{-3}$

$W = 60 \times 10^{-3}$

$W = 6 \times 10^2j$

hence, the work done to move the charge from infinity to point p will be 0.06 j.

Answer 2

Answer:

w=0.06J

Explanation:

We should to calculate the work done to move the change from inifinity to point p.

Now, by using the formula of potential difference :-

V=W/Q.

also,

W=V*Q

put the given value,

W=12*5*10^-3

W=60*10^-3

W=6*10^2 j.

.

. . HENCE, THE WORK DONE TO MOVE THE CHANGE FROM INFINITY TO POINT P WILL BE 0.06J.

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