Question

hay!!
dear user
please give me own answer don't give a spam answers

A coin is tossed 200 times and it is found that head comes up 114
times and tail 86 times

if a coin is tossed at random, what is the probability of getting
(I) a head, (II) a tail

please explain

Answer 1

Hey there!

Given number of events = 200 .

Number of heads = 114
Number of tails = 86 .

Probability = Favourable outcomes / Total outcomes.

Probability of getting a tail = 86/200 = 43/100 = 0.43

Probability of getting a head = 114/200 = 57/100 = 0.57

Usually probability is expressed in terms of fractions.

Hope helped!

Answer 2

hay!!

dear user

Total number of trials =>200
Number of heads=>114
Number of tails=>86

(I) Let E be the event of getting a head.

p(getting a head)=p(E) = number of heads coming up/total number of trials

=> 114/200 = 0.57

(II) Let F be the event of getting a tail.

p(getting a tail) = p(F) = number of tails coming up /total number of trials

=> 86/200=0.43

Clearly, when a coin is tossed, then E and F are the only possible outcomes, and p(E) +p(E) =(0.57+0.43) => 1.

I hope it's help you