Question

Haydee prepared a solution
with 3mL of potassium chloride
(KCl) in 200 mL of water is
prepared. Calculate the percent
by volume concentration of the
solution.
A. 1.46% B.1.48 %
C. 1.49 % D. 1.50%

Answer 1

Explanation:

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In order to make the coefficients of x equal multiply the equation 8x + 5y = 9 by 3 and equation 3x + 2y = 4 by 3

Then we get the equations: 24 x + 15 y = 27 . . . . . . . . . ( 1 )

24 x + 1 6 y = 32 . . . . . . . . . ( 2 )

Subtract Equation (1) from Equation (2) to eliminate x , because the coefficients of x are the same.

So, we get ( 24 x − 24 x ) + ( 16 y − 15 y )

= 32 − 27

i.e. y = 5

Substituting this value of y in the equation 8x + 5y = 9 ,

we get 8x + 25 = 9

i.e. 8x = − 16

i.e. x = −2

Hence, the solution of the equations is x = − 2 , y = 5 .

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Answer 2

Given: Haydee prepared a solution with 3mL of potassium chloride (KCl) in 200 mL of water is prepared.

To find: We have to find out the percent by volume concentration of the solution.

Solution:

The percentage of volume is a ratio of volume of KCl to total volume multiplied by 100.

The volume of KCl is 3 ml.

Total volume is a sum of volume of KCl and water.

So, total volume is (200+3=203) ml.

So, the percentage by volume concentration is-

$\frac{3}{203} \times 100 = 1.48$

The percent by volume concentration of the solution is 1.48%.

The correct option is B 1.48%.