Chemistry, asked by gounderpriya, 1 month ago

HC =C - CH - CH,
HC = C - CH2
H,
th
och si
Problem 14.3:
Complete the following table
Structural formula
CH, -CH - CH - CH
CH,
at fo
IUPAC Name
Prefix
be loc
e 110
2 - methyl
2 - methylbutane
Numbering
&- E-&-
C С
С
1 2 3
C-C-C
С
CH
CH - C - CH,
1
2,2-dimethyl 2,2-dimethylpropane
CH
H
CH, - CH - CH-CH
CH, CH, CH
CH, -CH-CH-CH-CH2-CH,
CH, CH - CH
CH, -CH - CH-CH - CH - CH,
CH, CH,
С.Н. CH
C
CH,
С.Н.
214​

Answers

Answered by sarwa
0

Answer:

eps, as indicated on the examples below:

•Step 1. Find the longest continuous carbon chain. Determine the root name for this

parent chain. In cyclic compounds, the ring is usually considered the parent chain, unless it is

attached to a longer chain of carbons; indicate a ring with the prefix “cyclo” before the root

name. (When there are two longest chains of equal length, use the chain with the greater number

of substituents.)

•Step 2. Number the chain in the direction such that the position number of the first

substituent is the smaller number. If the first substituents from either end have the same number,

then number so that the second substituent has the smaller number, etc.

•Step 3. Determine the name and position number of each substituent. (A substituent on

a nitrogen is designated with an “N” instead of a number; see Section III.D.1. below.)

•Step 4. Indicate the number of identical groups by the prefixes di, tri, tetra, etc.

•Step 5. Place the position numbers and names of the substituent groups, in alphabetical

order, before the root name. In alphabetizing, ignore prefixes like sec-, tert-, di, tri, etc., but

include iso and cyclo. Always include a position number for each substituent, regardless of

redundancies.

Short Summary of IUPAC Nomenclature, p. 4

Examples

1-sec-butyl-3-nitrocyclohexane

(numbering determined by the

alphabetical order of substituents)

3-bromo-2-chloro-5-ethyl-4,4-dimethyloctane 3-fluoro-4-isopropyl-2-methylheptane

6 7 6

4

5

4 5

1

3

3

2

2

1

8 7

6

5

4

1 2 3

H3C CHCH2CH3

NO2

CH CH CHCH3

CH2CH2CH3

CH3

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