Question

HCE of
of 4 (x²-4), 6(x²-x - 2) and 12(x² + 3x-10)​

Answer 1

Answer:

Step-by-step explanation:

Factors of each term are:-  

4($x^{2}$-4) =          2 x 2 (x-2) (x+2)

6($x^{2}$-x-2) =       2 x 3 (x-2) (x+1)

12($x^{2}$+3x-10) = 2 x 2 x 3 (x+5)(x-2)

H.C.F. = Common from all terms

So H.C.F. = 2(x-2)  Answer.

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