Question

hcf 120, 220, 360 find the hcf​

Answer 1

Answer:

120= 2×2×2×3×5

220= 2×2×5×11

360 = 2×2×2×3×3×5

here in all common is 2×2

i.e.4

Answer 2

Given: $120, 220, 360$

We have to find the HCF of the above numbers.

As we know that, the greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

We are solving in the following way:

We have,

$120, 220, 360$

First, we will find the factors of the above numbers:

The factors of $120$ are: $1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120$

The factors of $220$ are: $1, 2, 4, 5, 10, 11, 20, 22, 44, 55, 110, 220$

The factors of $360$ are: $1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 18, 20, 24, 30, 36, 40, 45, 60, 72, 90, 120, 180, 360$

From the above, we can see that$20$ is the largest positive integer that divides each of the given numbers.

So, the greatest common factor(HCF) is$20$.

Hence, we get the HCF is$20$.