Question

hcf 188, 216, 310find the hcf​

Answer 1

Answer:

Hi mate ,

Good morning ,

Have a nice day ✌️

Here is your answer :

188 = 2 × 2 ×47

216 = 2×3×2×3

310 = 2×5×31

So , there is only one common no. = 2

So , the HCF ( 188 , 216,310) = 2

Hope it help you ✌️❣️

Mark as brainliest answer and follow me

Answer 2

Given: The numbers are$188, 216, \ and\ 310$.

We have to find the HCF of the above numbers.

As we know that the greatest common divisor(HCF) of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

We are solving in the following way:

We have,

The numbers are$188, 216, \ and\ 310$.

First, we will find the factors of the above numbers.

The factors of 188 are: $1, 2, 4, 47, 94, 188$

The factors of 216 are: $1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 27, 36, 54, 72, 108, 216$

The factors of 310 are: $1, 2, 5, 10, 31, 62, 155, 310$

From the above, we can see that$2$ is the largest positive integer that divides each of the given numbers.  

Then the greatest common factor(HCF) is$2$.

Hence, the HCF of the given numbers is$2$.