Question

Hcf
48, 64,80please you con help me to solve this questions ​

Answer 1

Answer:

Hcf is 16

hope it will help u

Answer 2

Answer:

Step-by-step explanation:

• First we'll find HCF of 48

2 × 24 = 48

2 × 12 = 24

2 × 6 = 12

2 × 3 = 6

3 × 1 = 3

• So the factors of 48 are 2,2,2,2 and 3.
• Now we'll find HCF of 64

2 × 32 = 64

2 × 16 = 32

2 × 8 = 16

2 × 4 = 8

2 × 2 = 4

2 × 1 = 2

• So, the factors of 64 are 2,2,2,2,2and 2.
• Now we'll find the HCF of last digits 80!

2 × 40 = 80

2 × 20 = 40

2 ×  10 = 20

2 × 5 = 10

5 × 1 = 5

• So the factors of 80- are 2,2,2,2 and 5.
• Now we are going to take common and we'll write like this.

Factors of 48 = 2 × 2 × 2 × 2 × 3

Factors of 64 = 2 × 2 × 2 × 2 × 2 × 2

Factors of 80 = 2 × 2 × 2 × 2 × 5

• We can easily make four pairs of two as there are twos in all four rows except fifth and sixth as there is 3 and 5 in the fifth one and only a single 2 in the sixth one.
• SO after making four pairs of two we'll multiply them like

           ⇒ 2 × 2 × 2 × 2

           ⇒ 4 × 4

           ⇒ 16 Ans∞

→ Hope it helps :)