HCF and LCM are 9 and 360. if one of the number is 45 .
find other
Answers
Answered by
3
Let 2 numbers be a and b
a * b =HCF(a, b) * LCM(a, b)
45*b=9*360
b=9*360/45
b=72
Hope it helps you...
a * b =HCF(a, b) * LCM(a, b)
45*b=9*360
b=9*360/45
b=72
Hope it helps you...
Answered by
3
product of two nos. =HCF *LCM
45*x=9*360
x=
![(9 \times 360 ) \div 45 (9 \times 360 ) \div 45](https://tex.z-dn.net/?f=%289+%5Ctimes+360+%29+%5Cdiv+45)
![9 \times 8 = 72 9 \times 8 = 72](https://tex.z-dn.net/?f=9+%5Ctimes+8+%3D+72)
the other no. is 72
thank you
45*x=9*360
x=
the other no. is 72
thank you
mandeep274:
thanks a lot
Similar questions