Question

hcf and lcm is 3 snd 180 . if one number is 27 find other number .​

Answer 1

Answer:

$given - \\ HCF \: of \: two \: numbers = 3 \\ and \: their \: LCM \: = 180 \\ one \: number = 27 \\ let \: one \: number \: = a = 27 \\ and \: another \: number = b \\ we \: know - \\ a \times b = LCM \times HCF \\ 27 \times b = 180 \times 3 \\ b = \frac{180 \times 3}{27} \\ b = \frac{180}{9} \\ b = 20 \\ verifying \: - \\ a \times b = LCM \times HCF \\ 27 \times 20 = 180 \times 3 \\ 540 = 540 \\ LHS \: = RHS \:$

another number (b)= 20.

hope it helps.

Answer 2

given−

HCFoftwonumbers=3

andtheirLCM=180

onenumber=27

letonenumber=a=27

andanothernumber=b

weknow−

a×b=LCM×HCF

27×b=180×3

b=

27

180×3

b=

9

180

b=20

verifying−

a×b=LCM×HCF

27×20=180×3

540=540

LHS=RHS

another number (b)= 20.

hope it helps.