Question

HCF and LCM of two numbers are respectively 4 and 48.If one number is 12,other number is

Answer 1

In the above Question , the following information is given -

HCF and LCM of two numbers are respectively 4 and 48 .

One of the numbers is 12 .

To find -

Find the other number.

Solution -

Here , there are two numbers, 12 and suppose x .

Now ,

HCF of these numbers = 4 .

LCM of these numbers = 48 .

Now , we know that -

HCF × LCM = Product of numbers .

So ,

4 × 48 = 12x

=> x = 16 .

Thus , the other number is 16 .

This is the required answer.

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Answer 2

Step-by-step explanation:

Given,

HCF(a,b)= 4

LCM(a,b)=48

Let 'a' be 12

Given two positive integers a and b,

HCF(a,b) × LCM(a,b) = Product of two numbers(a,b)

4×48=12×b

b=4×48/12

b=16

Therefore the other number, b is 16

For verification,

HCF(a,b)×LCM(a,b)= 4×48=192---------(1)

Also,

Product of two numbers(a,b)=12×16=192-----------(2)

Since, (1) and (2) are equal.

Hence verified.