Hcf by 240 and228 using
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Apply EDto 240 and 228
240 = (228×1)+12
Apply EDL to 228 and 12
228 = (12×19)+0
So,HCF of 240 and 228 is 12.
240 = (228×1)+12
Apply EDL to 228 and 12
228 = (12×19)+0
So,HCF of 240 and 228 is 12.
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