Question

HCF by common division method .99,33,121

Answer 1

Answer:

11 is HCF of given numbers 99, 33, 121.

Step-by-step explanation:

HCF by common division method

• In this method, divide the largest number by the smallest number among the given numbers until the remainder is zero. The last divisor will be the HCF of given numbers.

Steps are as follows:

• Step 1: Divide the largest number of the given numbers by the smallest number.

• Step 2: Take divisor as the new dividend and remainder as  new divisor, i.e. we have to divide the first divisor by the first remainder.

• Step 3: Proceed till the remainder is zero . Then last divisor will be the HCF of the two given numbers.

To find out HCF of three given numbers 99,33,121 using division method, we have to follow the following steps:

• Step 1: Find out the HCF of any two numbers from the given numbers using division method .

• Step 2: Now, find out the HCF of the third number and the HCF obtained in step 1 using division method.

• Step 3: HCF obtained in step 2 will be the HCF of the three given numbers.

HCF of 99,33,121 by common division method :

Step 1:

• Find the HCF of 121 and 33 first.

• divide the largest number 121 by the smallest number 33 : 33)121 (3

        Remainder :121-99= 22

• Take divisor as the new dividend and remainder as  new divisor

        so, dividend = 33 and divisor = 22  :     22) 33( 1

        Remainder :33-22=11

• Take divisor as the new dividend and remainder as  new divisor
• so, dividend = 22 and divisor = 11  :     11) 22( 2

       Remainder :22-22=0

Hence, 11 is HCF of given numbers  33, 121.........................(i)

Step 2:

• Now we have to find the HCF of 99 and 11.
• Divide the largest number 99 by the smallest number 11 : 11)99 (9
• Remainder :99-99= 0

Hence, 11 is HCF of given numbers 99, 33, 121.

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Answer 2

Answer:

11 is the required HCF of 99, 33, and 121.

Step-by-step explanation:

Explanation:

Given that, 99, 33, and 121.

• HCF - The greatest number that divides each of the two or more numbers is known as the HCF, or the highest common factor.

• The Greatest Common Measure and Greatest Common Divisor are other names for HCF. The highest number is divided by the smallest number.

• Divide the first divisor by the first remainder, using the divisor as the new dividend and the remainder as the new divisor.

• Continue until the remainder is 0 and the HCF of the given numbers is the final divisor.

Step 1:

From the question, we have,  99, 33, 121

First, we divide 121 by 33

              33) 121 (3

                  -99

                       22)33( 1

                            -22

                             11)22(2

                                -22

                                 xxx

This can be written as,

121 = 33 × 3 + 22

33 = 22 ×1 + 11

22 = 11 × 2 + 0

Here we can see that on dividing 22 by 11 we get 0 as the remainder.

Now, we divide 99 by 11

 11 ) 99( 9

      -99

       xx

⇒ 99 = 11 × 9 + 0

Therefore, 11 is the HCF of 99, 33, 121.

Final answer:

Hence, 11 is the required HCF of 99, 33, and 121.

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