hcf by euclids algorithm method
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Step 1 : choose bigger number : 1188>504
On dividing 1188 by 504, we get
Quotient = 2 and remainder = 180
⇒1188=504×2+180
Step 2: on dividing 504 by 180
Quotient = 2 and remainder = 144
⇒504=180×2+144
Step 3 : on dividing 180 by 144
quotient = 1 and remainder = 36
⇒180=144×1+36
Step 4 : On dividing 144 by 36
quotient = 4 and remainder =0
⇒144=36×4+0
Since remainder is zero, stop the process
therefore, HCF of 1188 and 504 is 36
iii) To find HCF of 960 and 1575
1575 = 960 × 1 + 615
960 = 615 × 1 + 345
615 = 345 × 1 + 270
345 = 270 × 1 + 75
270 = 75 × 3 + 45
75 = 45 × 1 + 30
45 = 30 × 1 + 15
30 = 15 × 2 + 0
Now remainder is equal to zero.
Therefore ,
HCF ( 960 , 1575 ) = 15
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