Hcf of 1.2 and 0.12 in Euclid's division lemma
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Answered by
5
by euclids division lemma
a=bq+r here ,
a=1.2 ,b=0.12
we have to carry the alogrithm untill r=0 and find b at that stage
1.2=0.12×10 +0 ,here r =0
thus h.c.f = b = 0.12
a=bq+r here ,
a=1.2 ,b=0.12
we have to carry the alogrithm untill r=0 and find b at that stage
1.2=0.12×10 +0 ,here r =0
thus h.c.f = b = 0.12
Answered by
15
Answer:
Step-by-step explanation:
Let’s take two fractions (a/b) and (c/d).
To find LCM and HCF of (a/b) and (c/d) the generalized formula will be:
H.C.F = H.C.F of numerators / L.C.M of denominators
L.C.M = L.C.M of numerators / H.C.F of denominators
so,HCF of (1.2 , 0.12) =HCF of (12/10 , 12/100)=HCF of (12, 12) /LCM of (10, 100)
since=>HCF of (12 , 12) = 12 and LCM of (10 , 100) = 100
so, HCF of (1.2 , 0.12) =12/100 =0.12
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