Question

hcf of 12(a^6-a²b²c²) and 20(a⁴b²c²+a²b³c²)
step by step explanation
not direct answer​

Answer 1

4 a^2

Step-by-step explanation:

HCF [12(a^6- a^2b^2c^2),20(a^4b^2c^2+a^2b^3c^2) ]

=12a^2(a^4-b^2c^2),20a^2(a^2b^2c^2+ b^3c^2)

=4a^2[ 3(a^4-b^2c^2),5(a^2b^2c^2-b^3c^2)]

HCF = 4a^2

Answer 2

Answer:

1st exp = 2×2×3×a^2((a^2)^2-(bc)2)

=2×2×3×a^2(a^2-bc)(a^2