Question

HCF of 1268,1028 find the HCF​

Answer 1

Answer:

Step-by-step explanation:

Finding HCF using prime factorization

The factors of 1028 are: 1, 2, 4, 257, 514, 1028

The factors of 1268 are: 1, 2, 4, 317, 634, 1268

Common factors-1,2,4

Highest common factor-4

GCF/HCF=4

Answer 2

Answer:

The HCF of the given data is 4.

Step-by-step explanation:

Given: The numbers are 1268 and 1028.

We have to find the HCF of the above numbers.

• As we know that the greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

We are solving in the following way:

We have,

The numbers are 1268 and 1028.

First, we will find the factors of the above numbers.

The factors of 1028 are: $1, 2, 4, 257, 514, 1028$

The factors of 1268 are:$1, 2, 4, 317, 634, 1268$

From the above, we can see that 4 is the largest positive integer that divides each of the given integers.

Therefore the greatest common factor(HCF) is 4.

NOTE:

Q. Find the HCF of 1268 and 1028.