Question

HCF of 1344,1856,1752​

Answer 1

Answer:

64

HCF of 1344 , 1856 and 2752 = 2 × 2 × 2 × 2 × 2 × 2 = 64. Hence, The greatest number which can divide 1354 , 1866 and 2762 leaving remainder 10 in each case is 64.

Step-by-step explanation:

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Answer 2

Answer:

Solution: 1354–10 = 1344

1866–10 = 1856

2762–10 = 2752.

Factors of

1344 = 2x2x2x2x2x2x3x7 = 2^6x3x7

1856 = 2x2x2x2x2x2x29 = 2^6x29

2752 = 2x2x2x2x2x2x43 = 2^6x43

HCF = 2^6 or 64.

The number is 64 which divides 1354, 1866, 2762, leaving a remainder of 10 in each case. Answer.