Math, asked by richi77, 9 months ago

hcf of 1470,2688 and 4032 in prime factorisation

Answers

Answered by Abhiram5566

3

Answer:

2688 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 7

4032 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 7

1470 = 2 × 3 × 5 × 7 × 7

HCF is 14

Step-by-step explanation:

Answered by abhayjii210

0

Answer:

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