Math, asked by skbehers8, 6 days ago

HCF of 14x²yz² and 21xy²z² is _____.l

Answers

Answered by aayushidhamecha1601

1

Answer:

7xyz²

Step-by-step explanation:

14x²yz² = 2*7*x*x*y*z*z

21xy²z² = 3*7*x*y*y*z*z

the common factors are, 7*x*y*z*z

i.e. HCF is 7xyz²

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