Question

HCF OF 16.58 M AND 8.32 M

Answer 1

Answer:

The sum of two numbers is 588 and their HCF is 49.

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Answer 2

Find the least number of square tiles by which the floor of a room of dimensions 16.58 m and 8.32 m can be covered completely.

Solution :

We require the least number of square tiles. So, each tile must be of maximum dimension.

To get the maximum dimension of the tile, we have to find the largest number which exactly divides 16.58 and 8.32. That is nothing but the H.C.F of (16.58, 8.32).

To convert meters into centimeters, we have to multiply by 100.

16.58 ⋅ 100 = 1658 cm

8.32 ⋅ 100 = 832 cm

H.C.F of (1658, 832) = 2

Hence the side of the square tile is 2 cm

Required no. of tiles :

= (Area of the floor) / (Area of a square tile)

= (1658 ⋅ 832) / (2 ⋅ 2)

= 344,864

Hence, the least number of square tiles required is 344,864.

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