Question

hcf of 161 and 192 by prime factorisation method​

Answer 1

$\huge \mathfrak{hello \: mate}$

Prime factors of 161=7×23=7^1×23^1

Prime factors of 192=2×2×2×2×2×2×3=2^6×3^1

➡We know that the HCF will be equal to the lowest power.

Here, 1 is the only common factor.

So, HCF(161,192)=1

Answer 2

Here is your answer ☺️☺️❤️❤️

❤️ 161 = 7 ❌23

❤️ 192 = 2❌2❌2❌2❌2❌2❌3

Therefore HCF = 1

Hope this helps you ☺️☺️❤️❤️

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