Question

HCF of 2/3,8/9,64/81,10/27 is

Answer 1

Given fractions are 2/3 , 8/9 , 64/81 , 10/27
The HCF of a fractional number= HCF of numerators/ LCM of denominators.
So, HCF of 2, 8, 64, 10 /LCM of 3, 9, 81, 27
= 2/81

Answer 2

Answer:

HCF of $\frac{2}{3}, \frac{8}{9},\frac{64}{81},\frac{10}{27}$ =$\frac{2}{81}$

Step-by-step explanation:

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HCF of fraction :

$\boxed{HCF\: of\: \frac{a}{b},\frac{c}{d},\frac{e}{f}\\\\=\frac{HCF\: of \: Numerator (a,c,e)}{LCM\: of \: Denominator (b,d,f)}}$

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Here ,

i)HCF of numerators (2,8,64,10) =2 -----(1)

ii) LCM of denominators (3,9,81,27) = 81 ----(2)

/* Since , 3,9,27 are factors of 81 */

Now,

HCF of $\frac{2}{3}, \frac{8}{9},\frac{64}{81},\frac{10}{27}$ = $\frac{HCF\: of \: Numerators}{LCM\: of \: Denominators}$

= $\frac{2}{81}$

Therefore,

HCF of $\frac{2}{3}, \frac{8}{9},\frac{64}{81},\frac{10}{27}$ =$\frac{2}{81}$

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