Question

Hcf of 2 numbers is 12 and their lcm is 6 times their hcf. If one number isblarger thanthe other num by 12What is the product of digits of smaller number​

Answer 1

Answer:

H.C.F(a,b) = 12 and L.C.M(a,b) = 6 × H.C.F(a,b) = 6×12 = 72. We need to find the value of 'b'. Thus, the other number is 24.

Answer 2

Answer:

The HCF of 2 numbers is 12 and their LCM is 6 times their HCF . If one number is larger than the other number by 12 , What is the product of digit of the smaller number ?

The other number is 24. Product of two numbers (a×b) = H.C.F(a,b) × L.C.M(a,b). One of the numbers is, a=36. Also, H.C.F(a,b) = 12 and L.C.M(a,b) = 6 × H.C.F(a,b) = 6×12 = 72.

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