Math, asked by jyoti16780, 5 months ago

HCF of 2(x²-y²) and 5(x³-y³)

Answers

Answered by kavitasetia09

2

Step-by-step explanation:

Since, x2−y2

=(x+y)(x−y)

x3−y3

=(x−y)(x2+xy+y2)

H.C.F.=(x−y)

Answered by garimarajput862

0

Answer:

${2x}^{2} - {2y}^{2} + {5x}^{3} - {5y }^{3}$

Step-by-step explanation:

it hope brainaly help

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