Question

hcf of 204,1190,1445

Answer 1

204:- 2x2x3x17

1190:-2x5x17x7

1445:-5x17x17

Therefore HCF:- 17

Answer 2

Answer:

$\red {HCF ( 204, 1190, 1445 ) }= \green {17}$

Step-by-step explanation:

$Resolve \: the \: numbers \:204,1190 \:and \:1445\\ into \: product \: prime \: factors .$

i)

2 | 204

________

2 | 102

________

3 | 51

________

**** 17

ii)

2 | 1190

_______

5 | 595

_______

7 | 119

_______

**** 17

iii)

5 | 1445

_______

17 | 289

_______

***** 17

Now,

$204 = 2 \times 2 \times 3 \times \pink {17}$

$1190 = 2 \times 5 \times 7 \times \pink {17}$

$1445 = 5 \times \pink {17^{2}}$

$\red {HCF ( 204, 1190, 1445 ) }= \pink {17}$

/* Product of the smallest power of each common prime factors of the numbers */

Therefore.,

$\red {HCF ( 204, 1190, 1445 ) }= \green {17}$

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