HCF of 210 and 55 with a process
Answers
Answered by
2
Answer:
HCF = 5
Step-by-step explanation:
210 = 7 x 3 x 2 x 5
55 = 11 x 5
HCF = 5
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Answered by
1
Answer:
5
Step-by-step explanation:
Applying Euclids division lemma on 210 and 55, we get
210 = 55×3+45
Since the remainder 45=0. So, we now apply division lemma on the divisor 55 and the remainder 45 to get
55=45×1+10
We consider the divisor 45 and the remainder 10 and apply division lemma to get
45=4×10+5
We consider the divisor 10 and the remainder 5 and apply division lemma to get
10=5×2+0
We observe that the remainder at this stage is zero. So, that last divisor i.e.
5 is the HCF of 210 and 55.
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