Math, asked by harshikaukanti, 9 months ago

HCF of 210 and 55 with a process

Answers

Answered by HimnishVPParmar
2

Answer:

HCF = 5

Step-by-step explanation:

210 = 7 x 3 x 2 x 5

55 = 11 x 5

HCF = 5

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Answered by shrinivas26
1

Answer:

5

Step-by-step explanation:

Applying Euclids division lemma on 210 and 55, we get

210 = 55×3+45

Since the remainder 45=0. So, we now apply division lemma on the divisor 55 and the remainder 45 to get

55=45×1+10

We consider the divisor 45 and the remainder 10 and apply division lemma to get

45=4×10+5

We consider the divisor 10 and the remainder 5 and apply division lemma to get

10=5×2+0

We observe that the remainder at this stage is zero. So, that last divisor i.e.

5 is the HCF of 210 and 55.

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