Math, asked by ayanaagarwl008, 7 months ago

HCF of 219,1102,1218

Answers

Answered by jss5245
0

Answer:

HCF=1

Step-by-step explanation:

Prime factors of 219=3x73

Prime factors of 1102=2x19x29

Prime factors of 1218=2x3x7x29

HCF=1

Answered by pandayahardik5
0

Answer:

HCF( 219,1102,1218 ) = 1

Step-by-step explanation:

Here, prime factorisation are:-

219 = 3*73*1

1102 = 2*19*29*1

1218 = 2*3*7*29*1

Hence,

HCF( 219,1102,1218 ) = Product of the smallest power of each common prime factor in the numbers.

Therefore, HCF= 1

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