Question

HCF of 21a^3b^7
and 35a^5b^5

is

(A) 7a^3b^5

(B) 7a^2b^4

(C) 7a^7b^2

(D) 7a^2b^2

Answer 1

A is the correct answer.

Answer 2

Answer:

Option(A)

Step-by-step explanation:

(i) Given polynomial is 21a³b⁷

Prime factorization of 21a³b⁷ = 3 * 7a³b⁷

(ii) Given polynomial is 35a⁵b⁵.

Prime factorization of 35a⁵b⁵ = 5 * 7a⁵b5.

Now,

HCF of 21a³b⁷ and 35a⁵b⁵:

= 7a³b⁵

Hope it helps!