Question

hcf of 2261,3059 and 3325

Answer 1

Here is your answer dear.☺

first factorize all the three no.

1st no.2261

2261=7×17×19

2nd no.3059

3059=7×19×23

3rd no.3325

3325=5×5×7×19

the common factors of all 3 no. 7×19

therefore,HCF=133

Answer 2

HEY YOUR ANSWER IS .....


By Euclid's Division Lemma ,

3325=3059×1+266

3059=266×11+133

266=133×2+0

Again..

2261=133×17+0

Therefore , HCF of 2261,3059 and 3325 = 133 .