Question

HCF of (2³*3²*5) , (2²*3³*5²) and(2²*3*5³*7) is:​

Answer 1

Answer:

we just need to multiply the common values in between all these numbers:

2³*3²*5

= 2*2*2*3*3*5

2²*3³*5²

= 2*2*3*3*3*5*5

2²*3*5³*7

= 2*2*3*5*5*5*7

Common numbers in all 3 values= 2*2*3*5

                                     when we multiply, we get,

                                                       = 60

therefore,

HCF=60