Math, asked by hari1170, 1 year ago

hcf of 24(6x^4-x^3-2x^2),20(2x^6+3x^5+x^4)​

Answers

Answered by kumarnetid
1

Answer:

Step-by-step explanation:

Hcf = 4x^2(2x+1).

Answered by Mayankrama
1

Answer:

P(x) =24(6x*4-x*3-2x*2)

=6×4×x*2(6x*2-x-2)

=6×4×x*2(6x*2-4x+3x-2)

=6×4×x*2[(2x+1) (3x-2) ]

=6×4×x*2(2x+1) (3x-2)

and

q(x) =20(2x*6+3x*5+x*4)

5×4×x*4(2x*2+2x+x+1)

5×4×x*4[(2x(x+1) +1(x+1) ]

5×4×x*2×x*2(2x+1) (x+1)

=HCF of P(x) and q(x) =4x*2(2x+1)

Step-by-step explanation:

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