HCF OF 2472,1284 and a 3rd number 'N' is 12. if LCM of these numbers is
23*32*5*103*107, then N?
A) 22*32*51
B) 22*32*71
C) 22*32*103
D) None of these
Answers
Step-by-step explanation:
The highest common factor (HCF) of any set of numbers is the largest possible number which divides the given numbers exactly without any remainder.
Given that, LCM (2472, 1284, and n) is 23 × 32 × 5 × 103 × 107
Let us express the numbers 2472, and 1284 as a product of prime numbers.
2472 = 2 × 2 × 2 × 3 × 103 (23 × 3 × 103)
1284 = 2 × 2 × 3 × 107 (22 × 3 × 107)
HCF (2472, 1284)= 2 × 2 × 3 (22 × 3)
'n' should also have one of the factors as HCF, and another factor as the missing element of other numbers from the LCM (i.e., 3 × 5)
Therefore,
n = 22 × 3 × (3 × 5)
n = 22 × 32 × 5
n = 4 × 9 × 5
n = 180
Therefore, if the HCF of 2472 and 1284 and a third number 'n' is 12 and if their LCM is 23 × 32 × 5 × 103 × 107, then the number 'n' is 180 (22 × 32 × 5