Question

HCF of 272 and 1032 by Euclid agoritm

Answer 1

by euclid"s division algorithm,

1032=272×3+216
272=216×1+56
216=56×3+48
56=48×1+8
48=8×6+0
here the remainder is 0,

hence the required hcf is 8

Answer 2

Hey mate, here is your answer:-)

1032= 272×3+216

272= 216×1+56

216= 56×3+48

56= 48×1+8

48= 8×6+0

Hence, the HCF of 272 and 1032 is 8

HOPE it helps!!!