Question

HCF of 27p²q², 63p³q³​

Answer 1

Answer:

hcf of these questions is -

$27p {}^{2} q ^{2} = 3 \times 3 \times 3$

$63p {}^{3} q {}^{3} = 7 \times 3 \times 3$

hcf=3×3=9

Step-by-step explanation:

hope that these answer is right

Answer 2

Step-by-step explanation:

$27 {p}^{2} {q}^{2} = {3}^{3} \times {p}^{2} \times {q}^{2}$

$63 {p}^{3} {q}^{3} = {3}^{2} \times 7 \times \times {p}^{3} \times {q}^{3}$

Minimum power

$HCF = {3}^{2} \times {p}^{2} \times {q}^{2}$

$HCF = 9 {p}^{2} {q}^{2} \: z \\ ans$

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