Math, asked by sreetesh84, 2 months ago

hcf of 2x³,7xy,14x²y² is

Answers

Answered by GaneshRM2006

0

Answer:

2x³=(2)(x)(x)(x)

7xy=(7)(x)(y)

14x²y²=(2)(7)(x)(x)(y)(y)

HCF(2x³,7xy,14x²y²) = x

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