Question

hcf of 3/16,5/12,7/18

Answer 1

heyyyyy
simple and easy using this a formula
$15xxxxxx$

hcf of all numerators by lcm of all denominator s okkkk pls make a brainiest okkkk

Answer 2

Answer:

The HCF of $\frac{3}{16},\frac{5}{12},\frac{7}{18}$ is $\frac{1}{2}$.

Step-by-step explanation:

We are given three rational numbers

$\frac{3}{16},\frac{5}{12},\frac{7}{18}$

We have to find the HCF means highest common factor

To find HCF then we factorize each given rational number

First we find the factor of rational number $\frac{3}{16}$

$\frac{3}{16}=3\times \frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}$

Then find the factors of second rational number $\frac{5}{12}$

$\frac{5}{12}=5\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{3}$

Now , we are finding the factors of third rational number$\frac{7}{18}$

$\frac{7}{18}=7\times\frac{1}{2}\times\frac{1}{3}\times\frac{1}{3}$

We can see that the highest common factor of three given rational numbers is $\frac{1}{2}$

HCF=$\frac{1}{2}$

Hence, the Highest common factor of given three number is $\frac{1}{2}$.