Question

HCF of 3 power 7 into 5 power cube into 2 power 4 and 3 power 2 into 7 power 4 into 2 power 8 ​

Answer 1

Answer:

The HCF of 3^7 * 5^3 * 2^4 and. 3^2 * 7^4 * 2^8

= 3^2 * 2^4

=9 * 16

=144

Answer 2

Question: HCF of $3^7\times5^3\times2^4$ and $3^2\times7^4\times2^8$ is

Answer:

The required HCF of the given numbers is 144.

Step-by-step explanation:

Highest common factor (HCF):-

• The largest (or the greatest) number which divides the two or more numbers.

Step 1 of 1

According to the question,

Consider the given two numbers as follows:

$3^7\times5^3\times2^4$

$3^2\times7^4\times2^8$

Notice that the numbers $3^2$ and $2^4$ are the common factors of the given numbers.

This implies the numbers $3^2$ and $2^4$ are the greatest (or largest) numbers which divides the given numbers.

$3^2\times2^4=9\times16$

           $=144$

Thus, the number 144 divides the numbers $3^7\times5^3\times2^4$ and $3^2\times7^4\times2^8$.

Final answer: The required HCF (Highest common factor) of the given numbers is 144.

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