HCF of 30 and 27 find the value of x and y d is equal to 30 X + 72 y
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i think x=9 and y=-9
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using Euclid's algorithm theHCF {30,72,}
72=30×2+12
30=12×12+6
12=6×2+6
HCF={30,72}=6
6=30-12×2
6=30-(72-30×2)2
6=30-2×72+30×4
6=30×5+72×-2
there force x=5,y=-2
also6=30×5+72(-2)+30×72-50×72
slove it to get
x=77,y=32
hence x and y are not unique
72=30×2+12
30=12×12+6
12=6×2+6
HCF={30,72}=6
6=30-12×2
6=30-(72-30×2)2
6=30-2×72+30×4
6=30×5+72×-2
there force x=5,y=-2
also6=30×5+72(-2)+30×72-50×72
slove it to get
x=77,y=32
hence x and y are not unique
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