Question

HCF of 36 54 and 138 in normal hcf method​

Answer 1

Answer:

Factors of

36=2×2×3×3

54=2×3×3×3

138=2×3×23

Common factors=2×3

Highest factor= 3

Therefore, the HCF of 36,54and 138 is 3.

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Answer 2

In this problem, we are assuming that we have to find the HCF of$36, 54,\ and \ 138$.

Q. Find HCF of$36, 54,\ and \ 138$ in the normal HCF method​.

Given: The numbers are$36, 54,\ and \ 138$.

We have to find the HCF of the above numbers.

As we know that the greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

We are solving in the following way:

We have,

The numbers are$36, 54,\ and \ 138$.

First, we will find the factors of the above numbers.

The factors of 36 are: $1, 2, 3, 4, 6, 9, 12, 18, 36$

The factors of 54 are: $1, 2, 3, 6, 9, 18, 27, 54$

The factors of 138 are: $1, 2, 3, 6, 23, 46, 69, 138$

From the above concept, we can see that$6$ is the largest positive integer that divides each of the integers.

Then the greatest common factor is$6$.

Hence, we get$HCF=6$