Question

HCF of 398 436 and 542 in division method

Answer 1

Step-by-step explanation:

we need to find the largest number that will divide 398,436,542 leaving remainders 7,11,15 respectively

hence,we need to find the HCF of three numbers

(398-7)=391

(436-11)=425

(542-15)=527

There fore HCF of (391,425,527)=17

Answer 2

Answer:

Clearly, the required number is the HCF of the numbers 398−7=391,436−11=425, and, 542−15=527.

First we find the HCF of 391 and 425 by Euclids algorithm as given below.

Clearly, H.C.F. of 391 and 425 is 17.

Let us now the HCF of 17 and the third number 527 by Euclids algorithm:

The HCF of 17 and 527 is 17. Hence, HCF of 391,4250 and 527 is 17.

Hence, the required number is 17.